The Jeopardy Greatest of All Time tournament will begin tonight, 1/7, on ABC at 8 ET. The contestants will be Ken Jennings, Brad Rutter and James Holtzhauer. The three will compete in a series of matches; the first to win three matches receives $1 million and the title of “Jeopardy! The Greatest of All Time.” The two non-winners will each receive $250,000.
“Jeopardy! The Greatest of All Time” will air as follows:
· TUESDAY, JANUARY 7 (8-9 p.m. EST)
· WEDNESDAY, JANUARY 8 (8-9 p.m. EST)
· THURSDAY, JANUARY 9 (8-9 p.m. EST)
· *TUESDAY, JANUARY 14 (8-9 p.m. EST)
· *WEDNESDAY, JANUARY 15 (8-9 p.m. EST)
· *THURSDAY, JANUARY 16 (8-9 p.m. EST)
*If necessary.
“Jeopardy! The Greatest of All Time” will air as follows:
· TUESDAY, JANUARY 7 (8-9 p.m. EST)
· WEDNESDAY, JANUARY 8 (8-9 p.m. EST)
· THURSDAY, JANUARY 9 (8-9 p.m. EST)
· *TUESDAY, JANUARY 14 (8-9 p.m. EST)
· *WEDNESDAY, JANUARY 15 (8-9 p.m. EST)
· *THURSDAY, JANUARY 16 (8-9 p.m. EST)
*If necessary.
Who Is the Greatest Jeopardy! Player of All Time? | J!Buzz | Jeopardy.com
To view videos on this site, you need to enable certain cookies.Privacy Settings On the heels of Jeopardy!’s Tournament of Champions, America’s Favorite Quiz Show is coming to ABC prime time in a multi-, consecutive-night event, “Jeopardy! The Greatest of All Time,” premiering Tuesday, January 7...
www.jeopardy.com
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